Question 1

need help converting the point slope form equation to slope intercpt form(y-1)=1/2(x-6)(y+10)=1/3(x+9)

Question 2

$\text{Answer : y = }(1)/(2)x\text{ - 2}$

The standard form of the slope intercept equation is written as

y = mx + b

Where m = slope and b = intercept

$\begin{gathered} (y\text{ - 1) = }(1)/(2)(x\text{ - 6)} \\ \text{Firstly, open the parentheses} \\ y\text{ - 1 = }(1)/(2)\cdot\text{ x - }(1)/(2)\cdot\text{ 6} \\ y\text{ - 1 = }(1)/(2)x\text{ - }(6)/(2) \\ y\text{ - 1 = }(1)/(2)x\text{ - 3} \\ \text{Isolate y} \\ y\text{ = }(1)/(2)x\text{ - 3 + 1} \\ y\text{ = }(1)/(2)x\text{ - 2} \end{gathered}$

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