Question

Supposed to 25% of the time Danny eat out twice a month 30% of the time he eats out once a month and 45% of the time he doesn’t eat out at all in a given month what is the expected value for the number of times daily eats out during a month

Answer 1

Expected value = 0.8 times per month

Step-by-step explanation

The mean of the probability distribution is called expected value and it is given as

E(X) = Σxᵢpᵢ

where

xᵢ = each variable = Number of times Danny eats out

pᵢ = probability of each variable

n = number of variables

p = probability of one variable

We need to set up the probability distribution first

xᵢ | pᵢ

2 | 0.25

1 | 0.30

0 | 0.45

E(X)

= (2 × 0.25) + (1 × 0.30) + (0 × 0.45)

= 0.5 + 0.3 + 0

= 0.8

Hope this Helps!!!