The area A of a portion of a circle is:

Where alpha is the angle of the portion of the circle. So, to find the radius, we clear 'r' from the expression above:

We can cancel the pi on the left of 'r' with the one on the right (the one that's dividing):

So, now we clear 'r':

![\sqrt[]{(380)/(7\pi)}=r](https://img.qammunity.org/2023/formulas/mathematics/high-school/pj4oe2bc8dtgkvx2wcixckofvforyypsqi.png)
So, the answer is:
![r=\sqrt[]{(380)/(7\pi)}km](https://img.qammunity.org/2023/formulas/mathematics/high-school/zfedh8ln3btf0nw8hfm9g3lpk7t3846gsr.png)