Question

a student throws a rock straight down words from a bridge into a river below if initial speed of the rock is 10.0 Ms and it takes 2.1 s to reach the river how high is the bridge

Answer 1

Since this is a free fall and all the motion is going down, let's make down the positive direction (that way we won't use minus signs). A free fall is an uniform accelerated motion, this means that we can use the formula:

`y-y_0=v_0t+(1)/(2)at^2`

In this case we know the initial velocity is 10 m/s, the time is 2.1 and the acceleration of gravity is 9.8 m/s^2. Plugging this values we have that:

`\begin{gathered} y-y_0=10(2.1)+(1)/(2)(9.8)(2.1)^2 \\ y-y_0=42.609 \end{gathered}`

This means that the rock fell 42.609 meters. Therefore, the bridge is 42.609 m tall.