From the data provided, we have the following;
Initial power output = 4 milliwatts
Power lost per reflection = 6% (OR 0.06)
We need to find a function that shows the power each time the laser beam is reflected off a mirror.
Note that the general equation for an exponential decay/loss is given as;
![\begin{gathered} y=a(1-r)^x \\ OR \\ f(x)=a(1-r)^x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/spq7b55km5ypms421sa0gucg2y1wjwmgww.png)
Note also that (1 - r) is often replaced by b. Therefore, the equation can be written as;
![\begin{gathered} f(x)=a(1-r)^x^{} \\ f(x)=ab^x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/aa5m3epx1axpuhmu46isfja52cqsz9h0tu.png)
Where the number of reflections is given by n and p(n) is a function of the number of reflections, we now have;
![p(n)=ab^n](https://img.qammunity.org/2023/formulas/mathematics/college/ns84ab1zugaq7d91n6hy233yagnat77cod.png)
Where the variables are;
![\begin{gathered} a=4\text{ milliwatts (initial value)} \\ r=0.06 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/c13fj9a29yb6gzfyll84ehovcyhbh128dx.png)
We now have the function as;
![\begin{gathered} p(n)=a(1-0.06)^n \\ p(n)=a(0.94)^n \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s64jvxz697vtjaxls95s6jihnl0ot39y58.png)
ANSWER:
![p(n)=a(0.94)^n](https://img.qammunity.org/2023/formulas/mathematics/college/vmw7gbgswzy7plnb7wni31v9cubtypm11b.png)