164k views
2 votes
Write an equation for the line that passes through the given point and is perpendicular to the graph of the given equation y=-2x-1; (2, -1)

User Cherrie
by
8.7k points

1 Answer

1 vote

The product of the slopes of the perpendicular lines = -1

If the slope of one is m, then the slope of the other is -1/m

The given equation is y = -2x - 1

The form of the equation is y = m x + b, where

m is the slope of the line

So the slope of the given line is m = -2

To find the slope of the perpendicular line reciprocal it and change its sign

The slope of the perpendicular line = 1/2

Substitute it in the form of the equation

y = 1/2 x + b

To find b substitute x and y of the equation by the coordinates of any point on the line

The line passes through point (2, -1), then

x = 2 and y = -1

-1 = 1/2 (2) + b

-1 = 1 + b

Subtract 1 from both sides to find b

-1 - 1 = 1 - 1 + b

-2 = b

The equation of the perpendicular line is

y = 1/2 x - 2


y=(1)/(2)x-2

User Aviah Laor
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories