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If n is a positive integer, then lim n→∞ 1/n[(1/n)^2+(2/n)^2+...+((n-1)/n)^2] can be expressed as...

User Foobnix
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1 Answer

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23 votes

Answer:

you ended up having = 1/n^3[1^2+2^2+3^2...(n-1)^2]

hope this helps :')

User Lbt
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