Let the length of the rectangle be "l" and width be "w".
The length is 4 times the width, we can write:

The area is given as 196. We know area of a rectangle is A = lw, where l is length and w is width. Thus, we can write:

Substituting the first equation into the second, we can solve for w. The process is shown below:
![\begin{gathered} 196=lw \\ 196=(4w)w \\ 196=4w^2 \\ w^2=(196)/(4) \\ w^2=49 \\ w=\sqrt[]{49} \\ w=7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w087bwfhz8am4xqa9pmxn3lod6vd5l19ud.png)
Now, using the 1st equation, we can solve for the length, "l". Shown below:

Answer:
Length = 28 inches
Width = 7 inches