Let the length of the rectangle be "l" and width be "w".
The length is 4 times the width, we can write:
![l=4w](https://img.qammunity.org/2023/formulas/mathematics/college/17zylbz85lvaye6ifb7xhbyw9wgbr7avye.png)
The area is given as 196. We know area of a rectangle is A = lw, where l is length and w is width. Thus, we can write:
![196=lw](https://img.qammunity.org/2023/formulas/mathematics/college/awakfxivvz15zqcf7wn4kylxcstyanry84.png)
Substituting the first equation into the second, we can solve for w. The process is shown below:
![\begin{gathered} 196=lw \\ 196=(4w)w \\ 196=4w^2 \\ w^2=(196)/(4) \\ w^2=49 \\ w=\sqrt[]{49} \\ w=7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w087bwfhz8am4xqa9pmxn3lod6vd5l19ud.png)
Now, using the 1st equation, we can solve for the length, "l". Shown below:
![\begin{gathered} l=4w \\ l=4*7 \\ l=28 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7x61y7uqctlkq6694xyjzgpk5kmos53fxz.png)
Answer:
Length = 28 inches
Width = 7 inches