6 cm, C. He did not square the length of the given leg
Step-by-step explanation
to solve this we need to use the Pythagorean theorem
T.P states for all rigth triangles:

then
Step 1
let
a=2.3
b=b
c=6.4
replace
![\begin{gathered} 2.3^2+b^2=6.4^2 \\ \text{now, we n}eed\text{ isolate b} \\ 5.29+b^2=40.96 \\ \text{subtract 5.29 in both sides} \\ 5.29+b^2-5.29=40.96-5.29 \\ b^2=35.67 \\ \text{square root in both sides} \\ \sqrt[]{b^2}=\sqrt[]{35.67} \\ b=5.97 \\ \text{rounded} \\ b=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6kxkhji065sxfqu3gkfy7ku6q2bysyyv5j.png)
Step 2
What mistake might the student have made?
check
A)He added the two given values

B) He subtracted the two given values

C)He did not square the length of the given leg
![\begin{gathered} 2.3^{}+b^2=6.4^2 \\ b^2=6.4^2-2.3 \\ b^2=38.66 \\ b=\sqrt[]{38.66} \\ b=6.21 \\ \text{rounded} \\ b=6.2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/yksiontzbgcx80pvrl056ynpg2wvj5p3c1.png)
D. He did not square the length of the hypotenuse
![\begin{gathered} 2.3^2+b^2^{}=6.4 \\ b^2=6.4-2.3^2 \\ b^2=1.11 \\ b=\sqrt[]{1.11} \\ b=1.05 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ch1tj5gbfxekfu7ktnri2ho89czrie7fqb.png)
so, the answer is C
I hope this helps you