Given the length and the expression that represents the width of a rectangle, you need to remember that:
• The area of a rectangle can be calculated by multiplying its dimensions:
![A=lw](https://img.qammunity.org/2023/formulas/mathematics/college/1uev9eqrb6cie54zfnubw0e3j6pmkw3cu2.png)
Where "l" is the length and "w" is the width.
• The perimeter of a rectangle is:
![P=2l+2w](https://img.qammunity.org/2023/formulas/mathematics/college/kglmgz1k7721scmpluhiwkuwdz056pgdjw.png)
Where "l" is the length and "w" is the width.
Then, knowing that:
![\begin{gathered} l=5 \\ w=x+2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/jh5hk9dmwtfyi5rjsyicxecprci236wqg3.png)
- You can set up that the area of this rectangle is:
![A=5(x+2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/f89wkewm8z9btfao4benru24aannmv6yz8.png)
Simplifying, you get:
![\begin{gathered} A=(5)(x)+(5)(2) \\ A=5x+10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/30qholmysgrc4mj9y64k6av199torluypg.png)
- And the perimeter is:
![\begin{gathered} P=(2)(5)+(2)(x+2) \\ P=10+2x+4 \\ P=2x+14 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/sjsn9zqo6kd4aohw1jafz8hjl41mcpurnq.png)
Hence, the answer is:
- The area is:
![A=5x+10](https://img.qammunity.org/2023/formulas/mathematics/high-school/ojdcan68sp5x4t9upx5wrrn11269gcdjso.png)
- The perimeter is:
![P=2x+14](https://img.qammunity.org/2023/formulas/mathematics/high-school/9hgjhcf04v6xlxhtpe5j06b3czqi2vgcyy.png)