1 Answer

Duanev · Answer 1 · 2023-11-11T14:57:09+0000

We have the following:

A.

First we find the slope of the line with the following points:

(0, 3) and (5,0)

now, for b, with the point (0,3)

$\begin{gathered} 3=-(3)/(5)\cdot0+b \\ b=3 \end{gathered}$

The equation is:

B.

The area is:

$\begin{gathered} A=(AC\cdot CB)/(2) \\ A=(3\cdot5)/(2)=(15)/(2) \\ A=7.5 \end{gathered}$

The area is 7.5 square units

for, perimeter:

$\begin{gathered} p=AC+CB+AB \\ AB^2=AC^2+CB^2 \\ AB^2=3^2+5^2=9+25=34 \\ AB=\sqrt[]{34} \\ p=3+5+\sqrt[]{34} \\ p=13.83 \end{gathered}$

The perimeter is 13.83 units

C.

when two lines are perpendicular they fulfill the following

$m_1\cdot m_2=-1$

therefore,

$\begin{gathered} -(3)/(5)\cdot m_2=-1 \\ m_2=(5)/(3) \end{gathered}$

Therefore, the equation is:

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