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Differentiate y=4x√3x²-8x

User Edo Post
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Okay, here we have this:

Considering the provided function, we are going to perform the requested operation, so we obtain the following:


\begin{gathered} y=4x√(3)x^2-8x \\ \\ y=4√(3)x^3-8x \\ \\ (dy)/(dx)=(d)/(dx)(4√(3)x^3)-(d)/(dx)(8x) \\ \\ (dy)/(dx)=12√(3)x^2-8 \end{gathered}

Finally we obtain that dy/dx is equal to: 12sqrt(3)x^2-8

User Ackdari
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