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- 10x + 100y = 30-3x + 30y = 9

User Marc Asmar
by
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1 Answer

4 votes

The given system is


\mleft\{\begin{aligned}-10x+100y=30 \\ -3x+30y=9\end{aligned}\mright.

First, we multiply the first equation by -3/10.


\mleft\{\begin{aligned}3x-30y=-9 \\ -3x+30y=9\end{aligned}\mright.

Then, we sum the equations


\begin{gathered} 3x-3x+30y-30y=9-9 \\ 0x+0y=0 \\ 0=0 \end{gathered}

According to this result, we can deduct that the system doesn't have any solutions because the lines represented by the equations are parallel.

User ArtixModernal
by
6.9k points
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