Question

What is the value of a in the function's equation? please help asap.

Answer 1

The general equation for a quadratic function is,

`f(x)=cx^2+bx+a`

The zeros of equation is -8 and 4, means that f(-8) = 0 and f(4) = 0.

Determine the equation for a, b and c.

`\begin{gathered} f(-8)=c(-8)^2+b(-8)+a \\ 0=64c-8b+a \\ a=-64c+8b \end{gathered}`
`\begin{gathered} f(4)=c(4)^2+b(4)+a \\ 0=16c+4b+a \\ a=-16c-4b \end{gathered}`

So equation is,

`\begin{gathered} -16c-4b=-64c+8b \\ 48c=12b \\ b=4c \end{gathered}`

Differentiate the function