Answer:
We can treat it like a triangle. The line from home plate bisects the 1st base
and 3rd base angle; so it's 45 degrees; call it angle B. The side opposite, b is
the side we want to find, (from 1st to dead center)
:
Let angle A be at 1st base then side a = 401
Let angle C is at center field, then side c = 90
:
Use the law of cosines:
b^2 = a^2 + c^2 - 2(a*c)Cos(B)
:
b^2 = 401^2 + 90^2 - 2(401*90)Cos(45)
:
b^2 = 16080 + 8100 - 2(36090)*.7071
:
b^2 = 168901 - 51038.5
:
b = √117863
b = 343.3 ft from 1st to straight-a-away center