Question

In ABCD, the measure of ZD=90°, CB = 37, BD = 12, and DC = 35. What is the valueof the sine of ZB to the nearest hundredth?

Answer 1

First we need to draw the triangle:

now that we have the triangle we have to remember that the sine function is defined as:

`\sin \theta=\frac{\text{opp}}{\text{hyp}}`

Then, in this case we have:

`\begin{gathered} \sin B=(35)/(37) \\ \sin B=0.95 \end{gathered}`

Therefore the sine of B is 0.95 to nearest hundreth