Question

Use trigaonamets functions as nessary to find the missing parts the triangle

Answer 1

Given a right angle triangle:

As shown on the acute angles is 21

So,

`\begin{gathered} \cos \text{ 21=}\frac{adjacent}{\text{hypotenuse}}=(6.4)/(H) \\ \\ H=(6.4)/(\cos 21)=6.855 \end{gathered}`

And:

`\begin{gathered} \tan 21=\frac{opposite}{\text{adjacent}}=(y)/(6.4) \\ \\ y=6.4\cdot\tan 21=2.457 \end{gathered}`

the third angle of the triangle =

`90-21=69`