1 Answer

Jaakko Karhu · Answer 1 · 2023-07-15T19:50:22+0000

1) Given data:

Area of square = 100 cm square

$\begin{gathered} a^2=100 \\ a=10\operatorname{cm} \end{gathered}$

The perimeter of square is,

$\begin{gathered} P=4a \\ P=4*10 \\ P=40\operatorname{cm} \end{gathered}$

2) Given data:

Perimeter of square = 116 cm

$\begin{gathered} 4a=116 \\ a=29 \end{gathered}$

The area os square is,

$\begin{gathered} A=a^2 \\ A=29*29 \\ A=841\operatorname{cm}\text{ square} \end{gathered}$

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