The calculated value of the numerical expression
is a. cube root of 4
How to evaluate the numerical expression
From the question, we have the following parameters that can be used in our computation:
the quantity 2 to the power of five sixths end quantity over the quantity 2 to the power of one sixth end quantity.
This means that
![2^\frac56 / 2^\frac16](https://img.qammunity.org/2023/formulas/mathematics/high-school/sphhk9szlsp8vgefc0dc61t1haokm9y3ms.png)
Applying the law of indices, we have
![2^\frac56 / 2^\frac16 = 2^(\frac56 - \frac16)](https://img.qammunity.org/2023/formulas/mathematics/high-school/e7vwijskyfquxixo93as4ajx6b7cmaif5v.png)
So, we have
![2^\frac56 / 2^\frac16 = 2^(\frac46)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5k4s5q2ffxsz4p1nwuxxu2wv3m3s2bs5r5.png)
Simplify
![2^\frac56 / 2^\frac16 = 2^(\frac23)](https://img.qammunity.org/2023/formulas/mathematics/high-school/yzqr2zuwlbbbgpe1nhcez0985b9cehkuk0.png)
This can be further expressed as
![2^\frac56 / 2^\frac16 = 4^(\frac13)](https://img.qammunity.org/2023/formulas/mathematics/high-school/f9qc8c8u30h4v2t0lxssxvh2we9meg5lxv.png)
![2^\frac56 / 2^\frac16 = \sqrt[3]{4}](https://img.qammunity.org/2023/formulas/mathematics/high-school/k0cpt6736mg21dvne01bffczr482yqpir5.png)
Hence, the numerical expression is cube root of 4