Question

Chauncey is studying a 250-mg sample of a radioasubstance has a half-life of 5 days. Write an equatsubstance, s, is left after n days?aS =b= 250 (3)s = 250 (3)s = 250 (0.5)s = 250 (0.5)$5nd

Answer 1

`s=250(0.5)^{(n)/(5)}`

Step by step explanation:

Exponential functions are represented by the following expression:

`\begin{gathered} f(x)=ab^x \\ \text{where,} \\ a=\text{initial amount} \\ b=\text{decay factor} \\ x=\text{time(days)} \end{gathered}`

Then, for this situation, we have an initial amount of 250, a decay factor of (0.5) in 5 days:

`s=250(0.5)^{(n)/(5)}`