A reference angle is the angle created by the terminal arm and X-axis, and must be in the same quadrant as the terminal arm.
The given angle is 255°. It is located at quadrant III, then we can find the reference angle by subtracting 180°:
![255\degree-180\degree=75\degree](https://img.qammunity.org/2023/formulas/mathematics/college/2bt6yal9y6jlasil1tk82k22cl96rtkveo.png)
The sin of 75 is:
![\sin 75\degree=0.9659](https://img.qammunity.org/2023/formulas/mathematics/college/3ffbe5thk30ft6lmdeved3l0p8hco0c7f8.png)
In quadrant III, the sine is negative, then the sin of 255° is equal to the sine of 75° but negative. So:
![\sin 255\degree=-0.9659](https://img.qammunity.org/2023/formulas/mathematics/college/sv857dxc18rmj6oe3ov5wuxb07y6p2wyft.png)
The answer is option C. sin75=0.9659 sin255=-0.9659