Given:
When the price of admission was $19, the attendance was about 1550 customers per week
And, when the price of admission was dropped to $16,
attendance increased to about 2350 per week
Let the attendance = A
And the price = p
The linear equation will be A = mp + b
Where (m) is the slope and (b) is the y-intercept
So,
When p = 19, A = 1550
When p = 16, A = 2350
So,

So,

we will find the value of (b) as follows:

So, the answer will be the linear equation is:
