As per given by the question.
There are given that a triangle.
Now,
Suppose given triangle is ABC.
Then, redraw the given triangle.
Now,
For finding the value of x, and y;
First find the value of x with the help of sine trigonometric function.
So,
![\sin 35^(\circ)=(AB)/(AC)](https://img.qammunity.org/2023/formulas/mathematics/college/5kouj16wun54cu7tfwvv0y722sbgfog5v5.png)
Then,
Substitute the value x for AB and 22 for AC.
SO,
![\begin{gathered} \sin 35^(\circ)=(AB)/(AC) \\ \sin 35^(\circ)=(x)/(22) \\ 0.57=(x)/(22) \\ x=0.57*22 \\ x=12.54 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9w6hcfyfh0oofjgt0sa2mozgn5mm7ejheu.png)
Now,
For finding the value of y,
Here, use pythagoras theorem in triangle ABC.
So, from the pythagoras theorem;
![AB^2+BC^2=AC^2](https://img.qammunity.org/2023/formulas/mathematics/college/eka6lkp48h046ttt94s5mfwhkh4avh9ovo.png)
Then,
Substitute the value in above formula;
So,
![\begin{gathered} AB^2+BC^2=AC^2 \\ x^2+y^2=(22)^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/152culjauq8t8fau4x7mepd8ox60n0kki4.png)
Now, put the value 12.54 for x,
So,
![\begin{gathered} x^2+y^2=(22)^2 \\ (12.54)^2+y^2=(22)^2 \\ 157.25+y^2=484 \\ y^2=484-157.25 \\ y^2=326.75 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ws2m59n4vexwqt557jszlwi0cs6jweit76.png)
Then,
![\begin{gathered} y^2=326.75 \\ y=\sqrt[]{326.75} \\ y=18.076 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/35pd7rrvtirh3862tv9x213f18517d37ll.png)
Hence, the value of x is 12.54 and the value of y is 18.076.