Assuming the dashed lines are parallel and perpendicular to the base, we can start by draw a third parallel line that passes through C and naming some distances:
Now, we can see that the given angles are alternate interior angles with respect to the angles formed by the new perpendicular line and the lines AC and BC:
Now, we can see that b and the base a + 24 are related with the tangent of 48°:

Also, b and a are related with the tangent of 17°:

We can solve both for b and equalize them:

Now, we can relate a and x with the sine of 17°:

And x is the distance between A and C, the storm. Thus the answer is approximately 31.2 miles, fourth alternative.