The given functions are
f(x) = x^2 - 5
g(x) = 3x - 1
To find 2g(f(- 5)), we would first find f(- 5)
To find f(- 5), we would substitute x = - 5 into f(x) = x2 - 5. It becomes
f(- 5) = (- 5)^2 - 5
f(- 5) = 25 - 5
f(- 5) = 20
Then, we would substitute f(- 5) = 20 into g(x) = 3x - 1
Thus,
g(f(- 5) = 3*20 - 1
g(f(- 5) = 60 - 1
g(f(- 5) = 59
Therefore,
2g(f(- 5)) = 2 * 59 = 118