Question

7. Consider the line below.A. Find two points on this line with whole number coordinates.B. Find an equation for this line in point slope form.C. Find the equation for this line in slope intercept form. Be sure to show your work-550-5

Answer 1

A.

Let take the x-intercept and the y-intercept.

• From the graph, the x-intercept (x-axis cutting point) is >>>

`(x_1,y_1)=(1,0)`

• The y-intercept (y-axis cutting point) is >>>

`(x_2,y_2)=(0,-1)`

Now, let's find the point slope and slope intercept form of the line.

B.

Point Slope Form

`y-y_1=m(x-x_1)`

Where m is given by the formula,

`m=(y_2-y_1)/(x_2-x_1)`

So, let's substitute the the points and find the point slope form:

`\begin{gathered} y-y_1=m(x-x_1) \\ y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1) \\ y-0=(-1-0)/(0-1)(x-1) \\ y-0=(-1)/(-1)(x-1) \\ y-0=1(x-1) \end{gathered}`

Thus, the point-slope form is

`y-0=1(x-1)`

C.

The slope intercept form is given by

`y=mx+b`

Where

m is the slope and b is the y-intercept

Just re-arranging the point slope form will give us the slope intercept form. Shown below:

`\begin{gathered} y-0=1(x-1) \\ y=1(x-1) \\ y=x-1 \end{gathered}`

The slope intercept form is

`y=x-1`