Let's first list down the information given in the scenario:
a.) In 2 years ariel wants to buy a bicycle that costs 1,000.00
b.) She opens a savings account that earns 9% interest compounded quarterly
Question: How much will she have to deposit as principal to have enough money in 2 years to buy the bike?
To be able to determine the principal amount Ariel will need to deposit, let's use this formula for Compound Interest:
![\text{ A = }P(1\text{ + }((r)/(n))/(100))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/2hjuuavy3h0ixu6dlga94984eg2xj0jrpw.png)
Where:
A = Is the final amount/ cost of the bicycle = 1,000
n = Number of times the interest is being compounded = 4
r = Interest rate = 9%
t = No. of periods elapsed/ No. years the principal money be deposited
P = Principal amount/ amount to be deposited
Let's now find the principal amount:
![\text{ A = }P(1\text{ + }((4)/(n))/(100))^(nt)\text{ }\rightarrow\text{ 1,000 = }P(1\text{ + }((9)/(4))/(100))^(4(2))](https://img.qammunity.org/2023/formulas/mathematics/college/8vk5kg2otkv0rt04yw024mcv8gs00rsmlj.png)
![\text{1,000 = }P(1\text{ + }(2.25)/(100))^8\text{ }\rightarrow\text{ 1,000 = }P(1\text{ + }0.0225)^8\text{ }\rightarrow1,000=P(1.0225)^8](https://img.qammunity.org/2023/formulas/mathematics/college/se80f0v1cnlwxituzyfxrmktjpk0vkwf27.png)
![\text{ P = }(1,000)/((1.0225)^8)\rightarrow\text{ P = }(1,000)/(1.19483114181)](https://img.qammunity.org/2023/formulas/mathematics/college/hrnjydi1z8shh27a35hjnm8iq09zka3hw0.png)
![\text{ P = 836.93835 }\cong\text{ 836.94}](https://img.qammunity.org/2023/formulas/mathematics/college/cd4sjsjmo4je69m3d5j25672t0yu5bor0f.png)
Therefore, Ariel must deposit a principal amount of 836.94 for her to be able to buy the bike in 2 years.