Question

Find the equation of a line passing through the point (0,1) and parallel to the line 2x – 3y = 6.

Answer 1

The given equation of the line is

`\begin{gathered} 2x-3y=6 \\ 3y=2x-6 \\ y=(2)/(3)x-2 \end{gathered}`

Hence slope of the line is

`(2)/(3)`

Since the line passing through (0,1) parallel to the given line then slope is same for both of them

Since (0,1) is a point so the intercept is c=1

So the equation is

`\begin{gathered} y=mx+c \\ y=(2)/(3)x+1 \end{gathered}`