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What value is a discontinuity of x^2+5x+2/x^2+2x-35

User Quantico
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1 Answer

1 vote

Solution:

Given the expression:


(x^2+5x+2)/(2x^2+2x-35)

A function f(x) has disconituity at x=a if


\lim_(x\to a)f(x)

exists and is finite.

The function is thus undefined at x=a or when


\lim_(x\to a)(f(x))\\e f(a)

From the given function, we have


\begin{gathered} (x^2+5x+2)/(x^2+2x-35) \\ factorize\text{ the denominator,} \\ (x^2+5x+2)/(x^2-5x+7x-35)=(x^2+5x+2)/(x(x-5)+7(x-5)) \\ \Rightarrow(x^2+5x+2)/((x-5)(x+7)) \end{gathered}

The function is undefined at


\begin{gathered} x-5=0 \\ \Rightarrow x=5 \\ x+7=0 \\ \Rightarrow x=-7 \end{gathered}

Hence, there is discontinuity at


x=5,\text{ x=-7}

User Bye
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