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Solve the equation algebraically. x2 +6x+9=25

User Izzo
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1 Answer

1 vote

We must solve for x the following equation:


x^2+6x+9=25.

1) We pass the +25 on the right to left as -25:


\begin{gathered} x^2+6x+9-25=0, \\ x^2+6x-16=0. \end{gathered}

2) Now, we can rewrite the equation in the following form:


x\cdot x+8\cdot x-2\cdot x-2\cdot8=0.

3) Factoring the last expression, we have:


x\cdot(x+8)-2\cdot(x+8)=0.

Factoring the (x+8) in each term:


(x-2)\cdot(x+8)=0.

4) By replacing x = 2 or x = -8 in the last expression, we see that the equation is satisfied. So the solutions of the equation are:


\begin{gathered} x=2, \\ x=-8. \end{gathered}

Answer

The solutions are:

• x = 2

,

• x = -8

User Nbonniot
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