Answer:
y = 4/3 x + 4
Explanation:
The general form of the equation of a line is given as
y = mx + c where m is the slope and c is the intercept on the y axis
where the slope m = (y2 - y1)/(x2 - x1)
Hence given the points (-6, -4) and (0, 4)
m = (4 --4) / (0 --6)
= (4+4)/(0+6)
= 8/6
= 4/3
For a line with given points (x1, y1), the equation is given as
y-y1 = m(x-x1)
Hence the equation of this line in slope-intercept form
y - -4 = 4/3(x --6)
y + 4 = 4/3(x + 6)
3y + 12 = 4x + 24
3y = 4x + 24 - 12
3y = 4x + 12
y = 4/3 x + 4
For a line with given points (x2, y2), the equation is given as
y-y2 = m(x-x2)
Hence the equation of this line in slope-intercept form
y-4 = 4/3(x - 0)
multiply through by 3
3y - 12 = 4x
3y = 4x + 12
y = 4/3 x + 4