The figure ABCD has the shape of a Rhombus with diagonals AC and BD.
To determine the area of a Rhombus you have to multiply the length of both diagonals and divide the result by 2, following the formula:
Where
p represents the horizontal diagonal
q represents the vertical diagonal
For the quadrilateral ABCD, the lengths of the diagonals are:
AC=6cm + 15cm =21cm
BD= 8cm + 8cm=16cm
![\begin{gathered} A=(AC\cdot BD)/(2) \\ A=(21\cdot16)/(2) \\ A=(336)/(2) \\ A=168\operatorname{cm}^2 \end{gathered}]()
The area of the figure is 168cm²