Question

A train is traveling at a constant speed of 105 mph how many feet does a travel in three seconds remember that 1 mile is 5280 feet

Answer 1

Person above is correct

Answer 2

We are given that a train is traveling at the following constant speed:

`v=\frac{105\text{ miles}}{hour}`

We are asked to determine the distance after 3 seconds. To do that, let's remember that speed is the ratio between distance and time, that is:

`v=(d)/(t)`

Where:

`\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}`

Since we want to determine the distance we will multiply both sides of the equation by "t":

`vt=d`

Now, we substitute the values:

`\frac{105\text{ miles}}{hour}*(3s)=d`

Since the velocity is given per unit of hour, we need to convert the 3 seconds into hours. We do that using the following conversion factor:

`1\text{hour}=3600s`

Now we multiply the time by the conversion factor:

`3s*(1h)/(3600s)=(1)/(1200)h`

Now we substitute in the formula for the distance:

`\frac{105\text{ miles}}{hour}*((1)/(1200)hour)=d`

Solving the operations:

`(7)/(80)miles=d`

Now, we convert the miles into feet using the given conversion factor:

`1\text{mile}=5280\text{feet}`

Now, we multiply by the conversion factor:

`d=(7)/(80)\text{miles}*(5280feet)/(1mile)`

Solving the operations:

`d=462feet`

Therefore, the distance is 462 feet.