A train is traveling at a constant speed of 105 mph how many feet does a travel in three seconds remember that 1 mile is 5280 feet

Question

asked Feb 2, 2023 152k views

2 Answers

Adilet Maratov · Answer 1 · 2023-02-09T06:20:12+0000

We are given that a train is traveling at the following constant speed:

$v=\frac{105\text{ miles}}{hour}$

We are asked to determine the distance after 3 seconds. To do that, let's remember that speed is the ratio between distance and time, that is:

Where:

$\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}$

Since we want to determine the distance we will multiply both sides of the equation by "t":

Now, we substitute the values:

$\frac{105\text{ miles}}{hour}*(3s)=d$

Since the velocity is given per unit of hour, we need to convert the 3 seconds into hours. We do that using the following conversion factor:

$1\text{hour}=3600s$

Now we multiply the time by the conversion factor:

Now we substitute in the formula for the distance:

$\frac{105\text{ miles}}{hour}*((1)/(1200)hour)=d$

Solving the operations:

Now, we convert the miles into feet using the given conversion factor:

$1\text{mile}=5280\text{feet}$

Now, we multiply by the conversion factor:

$d=(7)/(80)\text{miles}*(5280feet)/(1mile)$

Solving the operations:

Therefore, the distance is 462 feet.