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Write an equation for the line that passes through the point (2,2) and is perpendicular to -8x+y=8. Use slope-intercept form.

User Omri Luzon
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1 Answer

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Ok, first of all, let's put the equation of the line in the slope-intercept form:

-8x+y=8

y=8x+8

The slope of this line is m=8.

The slope of a perpendicular line is the negative reciprocal of the slope of the first line, so:

m2=-1/8

Now let's calculate the equation of the perpendicular linbe, using the given point, (2,2):

y-y1=m*(x-x1)

y-2 = -1/8(x-2)

y-2=-1/8x + 2/8

y=-1/8x +2/8 +16/8

y=-1/8x + 18/8

y= -1/8x + 9/4

The equation will be y= -1/8x + 9/4

User Jefflovejapan
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