Notice that the factor x is a common factor for all three terms. Then, factor out x:
![x^3-2x^2-35x=x(x^2-2x-35)](https://img.qammunity.org/2023/formulas/mathematics/college/bd2jcod5jq2m29sv1cl1bk4taxw8i6dvb7.png)
Notice that the factor x²-2x-35 is a quadratic expression.
Find two numbers whose sum is -2 and whose product is -35 to factor out the quadratic expression. Since 5-7 = -2 and (5)(-7)=-35, those two numbers are -7 and 5. Then, the quadratic expression can be factored out as:
![x^2-2x-35=(x-7)(x+5)](https://img.qammunity.org/2023/formulas/mathematics/college/mio87fzgzl7mc3uilghrlartltswlrsuso.png)
Then:
![x(x^2-2x-35)=x(x-7)(x+5)](https://img.qammunity.org/2023/formulas/mathematics/college/2slyxzu8moot0ke5hikzldl3xiubv9bm1z.png)
Then, the factorization of the given trinomial is:
![x^3-2x^2-35x=x(x-7)(x+5)](https://img.qammunity.org/2023/formulas/mathematics/college/1jy9kdarwe4t6igam3uq2i6x8tpq7cpnw3.png)
Therefore, the correct choice is option C) x(x-7)(x+5)