125k views
1 vote
Could you help walk me through this problem? I keep getting the problem wrong and I don't know why.

Could you help walk me through this problem? I keep getting the problem wrong and-example-1

1 Answer

3 votes

to solve this we can get the equation in the form

F(x)=a(x-X1)(x-X2)

where X1 and X2 are the values of X where the line cross the axial X

in this case

X1= -1

X2= 2

so the function will be

F(x)=a*(x+1)*(x-2)

now we need to find the value of a

So for this we can replace with a random point of the curve, for example the point x= 0 y=-2

So if we replace

-2=a*(0+1)*(0-2)

-2=a*1*-2

-2=a*-2

-2/-2=a=1

So the answer is:

F(x)=1*(x+1)*(x-2)

User Subdavis
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories