Question

y=4x+6slope: 4y-int: (0,6)why after graphing y-int, is the second point on the line given a slope of 4/1? shouldn't it be 4,0?

Answer 1

The given line is,

`y=4x+6`

Here, the slope is, 4 and y intecept is 6.

For x = 4, we have,

`y=4*4+6=16+6=22`

Therefore, the two points on the graph is, (0, 6) and (4, 22).

Now, for y = 1, we have,

`\begin{gathered} 1=4x+6 \\ 4x=-5 \\ x=-(5)/(4) \end{gathered}`