Step-by-step explanation
We are asked to find the change in the water level per hour for Patrick's swimming
We have to use the formula
![change\text{ in water level per hour=}\frac{Volume\text{ of water}}{Time\text{ taken to drain}}](https://img.qammunity.org/2023/formulas/mathematics/college/kgrzigo13ayhpw469f8y6iltp9nma9qp1s.png)
Thus
![change\text{ in water level per hour=}(9644.6)/(8)=1205.575\text{ gallons per hour}](https://img.qammunity.org/2023/formulas/mathematics/college/ydt8kja4oej2q7nmdh7axtbc9agc8os1e8.png)
Note: The rate will be negative because we are draining
Therefore, the change in water level will be -1205.58 gallons per hour