We will have the following:
First, we are given:
*Mass of the breaker: 1.1kg
*Mass of water: 3.3 kg
*Mass of metallic alloy: 4.2kg
*Density of the alloy: 5300kg/m^3
*Density of water: 1000kg/m^3
Now, we find the volume of water displaced by the alloy:
![V_{\text{w}}=4.2\operatorname{kg}\cdot\frac{m^3}{5300\operatorname{kg}}\Rightarrow V_w=(21)/(26500)m^3\Rightarrow V_w\approx7.92\cdot10^(-4)m^3]()
Then, from the reading in the hanging scale we will have the force experienced by the alloy due to the upthrust when placed in water, that is:

So:
![R=(4.2\operatorname{kg})(9.8m/s^2)-(1000\operatorname{kg}/m^3)((21)/(26500)m^3)(9.8m/s^2)]()

The reading on the lower scale is due to the weight of the water in the breaker and upthrust on the scale:

Finally:
![R=(9.8m/s^2)(1.1\operatorname{kg}+3.3\operatorname{kg})+(1000\operatorname{kg}/m^3)((21)/(26500)m^3)(9.8m/s^2)]()

So, the readin on the lower scale is approximately 50.9N.