Question

Can you break it down and help me out please?

Answer 1

Given

`x^2+x-2\ge0`

To find the solution.

Now,

It is given that,

`x^2+x-2\ge0`

Using factorization method,

`\begin{gathered} x^2+x-2=0 \\ x^2-x+2x-2=0 \\ x(x-1)+2(x-1)=0 \\ (x+2)(x-1)=0 \end{gathered}`

That implies,

`\begin{gathered} x+2\ge0,x-1\ge0 \\ x\ge-2,x\ge1 \end{gathered}`

Hence, the solution set is,