Question

Solve the quadratic equations in questions 1 – 5 by factoring.1. x2 – 49 = 02. 3x3 – 12x = 03. 12x2 + 14x + 12 = 184. –x3 + 22x2 – 121x = 05. x2 – 4x = 5

Answer 1

Given:

There are given the equation:

`-x^3+22x^2-121x=0`

Step-by-step explanation:

According to the question:

We need to find the value of x by using the factoring:

S0,

From the equation:

`-x^(3)+22x^(2)-121x=0`

Tthen,

`\begin{gathered} -x^(3)+22x^(2)-121x=0 \\ -x(x^2-22x+121)=0 \end{gathered}`

Then,

`\begin{gathered} -x(x^2-22x+121)=0 \\ x(x-11)^2=0 \\ x=0; \\ x-11=0 \\ x=11 \end{gathered}`

Final answer:

Hence, the value of x by using factor method is shown below:

`x=0,11`