Given:
Rita earns scores of 83, 87, 85, 88, and 90 on her five-chapter tests for a certain class.
And a grade of 82 on the class project.
First, we will find the average of the scores of the five tests
![5-tests\text{ }average=(83+87+85+88+90)/(5)=(433)/(5)=86.6](https://img.qammunity.org/2023/formulas/mathematics/college/qlpwtmto28zn2yos064hnplbtmmim0vek0.png)
The overall average for the course is computed as follows:
30% of the course grade ⇒ Rita get 86.6
30% of project grade ⇒ Rita get 82
40% of the final exam ⇒ let Rita get x
We will find the value of x provided that Rita will earn a "B" score
a "B" is an overall score greater than or equal to 80, but less than 90
So, we will find (x) as follows:
![(30*86.6+30*82+40*x)/(100)\ge80](https://img.qammunity.org/2023/formulas/mathematics/college/ru21zfrnn4taqc6wk85yekyvkq5ux2bdx9.png)
Solve the inequality to find (x):
![\begin{gathered} 5058+40x\ge8000 \\ 40x\ge8000-5058 \\ 40x\ge2942 \\ x\ge(2942)/(40) \\ \\ x\ge73.55 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kz0l5vm6ssonpg1u6r5cw9l5ebpopqkw50.png)
And the upper limit will be as follows:
![(30*86.6+30*82+40x)/(100)<90](https://img.qammunity.org/2023/formulas/mathematics/college/bdjzt8945nxlrqm58m2i7bogcthlb25ot4.png)
Solve to find (x):
![\begin{gathered} 5058+40x<9000 \\ 40x<9000-5058 \\ 40x<3942 \\ x<(3942)/(40) \\ \\ x<98.55 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u2xiok6uokbfy03i6inn9ohh8p68mbh4a2.png)
So, the answer will be:
To obtain a "B", Rita needs to score between 73.55 and 98.55