Question

In the triangle below, if < C = 62 °, what is the measure of angle B?

Answer 1

In the given triangle ABC

`BA=BC`

Then the triangle is isosceles

In the isosceles triangle, the base angles are equal

Since
`m\angle A=m\angle C`Since m
`m\angle A=62^(\circ)`In any triangle the sum of angles is 180 degrees, then

`m\angle A+m\angle B+m\angle C=180^(\circ)`

Substitute angles A and C by 62

`\begin{gathered} 62+m\angle B+62=180 \\ \\ m\angle B+124=180 \end{gathered}`

Subtract 124 from both sides

`\begin{gathered} m\angle B+124-124=180-124 \\ \\ m\angle B=56^(\circ) \end{gathered}`

The answer is b