Question

11.Solve the given equation over the interval [0, 271): 2 sin x++3 = 0.117and x=64757X=- and x=332лx= -- and x=3T57x= -- and x=6and x3

Answer 1

Question:

Solution:

Let the following trigonometric equation:

`2\sin (x)+\sqrt[]{3}=\text{ 0}`

Subtract the root of 3 from both sides of the equation:

`2\sin (x)=-\sqrt[]{3}`

solve for sin(x):

`\sin (x)=\text{ -}\frac{\sqrt[]{3}}{2}`

Applying the trigonometric circle on the given interval, we obtain that the correct answer is:

`x\text{ = }(4\pi)/(3)\text{ , x = }(5\pi)/(3)`