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Identify whether the problem is "Sum of Two Cubes" or "Difference of Cubes". Then, factor the problem.x^3 - 8

User Illidanek
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We have in this case the difference of Perfect Cubes since we have:


x^3-8=x^3-2^3

We know that this case can be factored as follows:


a^3-b^3=(a-b)\cdot(a^2+ab+b^2)

If we have that:

a = x

b = 2

Then, we have:


(x-2)\cdot(x^2_{}+2x+2^2)=(x-2)\cdot(x^2+2x+4)

Therefore, the factored form of the perfect cube (for difference) is:


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User Castletheperson
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