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5 votes
For / (x) = 4x+1 and g(x)=x2-5, find

User Beech
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5 votes

\begin{gathered} f(x)=4x+1 \\ g(x)=x^2-5 \end{gathered}

We need to find g(x)/f(x) so we will put them over each other as a fraction


(g(x))/(f(x))=(x^2-5)/(4x+1)\text{ , x}\\e(-1)/(4)

In any algebraic fraction, denominators can not be zero, so we avoid any values make it equal to zero like -1/4 in our question