You have the following equation:
9x - 5y = 6
In order to find the equation of the line, you first calculate the slope of the previous line equation:
9x - 5y = 6 subtract 9x both sides
9x - 9x - 5y = 6 - 9x simplify
-5y = -9x + 6 divide by -5 both sides
-5y/(-5) = -(9/5)x + 6/5 simplify
y = -(9/5)x + 6/5
y = -1.8x + 1.2
Then, the slope of the line is m=-1.8
Now, to find the equation of the line with the point (6,-2) you use the following formula for the slope of a line:
m=(y-yo)/(x-xo)
due to the required line is parallel to the line with slope -1.8, the slope of the required line is the same, m = -1.8. xo and yo are the given coordiantes of the given point (6,-2), that is, xo = 6 and y = -2. You replace these values into the formula for the slope and solve for y:
m = (y - (-2))/(x - 6) = (y + 2)/(x - 6) multiply both sides by (x-6)
(x-6) m= y + 2
y = mx - 6m - 2 = (-1.8)x - 6(-1.2) - 2
y = -1.8x - 5.2
This last equation is the required equation