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Nitrogen and water react to form nitrogen monoxide and hydrogen, like this: N2(g) + 2H2O(g) → 2NO(g) +2H2(g)Also, a chemist finds that at a certain temperature the equilibrium mixture of nitrogen, water, nitrogen monoxide, and hydrogen has the following composition: compound pressure at equilibrium N2 0.25 M H20 1.3 M NO 0.33 M H2 1.2 MCalculate the value of the equilibrium constant for this reaction. Round your answer to significant digits.

User BPm
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1 Answer

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Answer: The value of the equilibrium constant for this reaction is 0.37

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
K_c

For the given chemical reaction:


N_2(g)+2H_2O(g)\rightarrow 2NO(g)+2H_2(g)

The expression for
K_c is written as:


K_c=([NO]^2* [H_2]^2)/([H_2O]^2* [N_2]^1)


K_c=((0.33)^2* (1.2)^2)/((1.3)^2* (0.25)^1)


K_c=0.37

Thus the value of the equilibrium constant for this reaction is 0.37

User Mark Lano
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