Question

Hi, can you help me answer this question, please, thank you!

Answer 1

Given:

mean, u = 0

standard deviation σ = 1

Let's determine the following:

(a) Probability of an outcome that is more than -1.26.

Here, we are to find: P(x > -1.26).

Apply the formula:

`z=(x^(\prime)-u)/(\sigma)`

Thus, we have:

`\begin{gathered} P(x>-1.26)=(-1.26-0)/(1) \\ \\ P(x>-1.26)=(-1.26)/(1)=-1.26 \end{gathered}`

Using the standard normal table, we have:

NORMSDIST(-1.26) = 0.1038

Therefore, the probability of an outcome that is more than -1.26 is 0.1038

(b) Probability of an outcome that