Question

How many moles of NaOH are in 21.4 mL of 1.29 M NaOH?

Answer 1

n = 0.0276 mol

Step-by-step explanation:

Required: Moles of NaOH

Given:

Volume of NaOH = 21.4 mL

Molarity/concentation = 1.29 M

Solution:

We will use the following equation to solve the problem:

`C\text{ =}(n)/(V)`

C is the concentration or molarity in mol/L or M, n is the number of moles in mol and V is the volume in L. Therefore we need to first convert mL to L.

1mL = 0.001 L

therefore 21.4 mL = 0.0214 L

Lets re-arrange the equation:

n = CV

n = 1.29 mol/L x 0.0214 L

n = 0.0276 mol